16x^2-24x-625=0

Solution for 16x^2-24x-625=0 equation:

16x^2-24x-625=0

a = 16; b = -24; c = -625;
Δ = b2-4ac
Δ = -242-4·16·(-625)
Δ = 40576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40576}=\sqrt{64*634}=\sqrt{64}*\sqrt{634}=8\sqrt{634}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8\sqrt{634}}{2*16}=\frac{24-8\sqrt{634}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8\sqrt{634}}{2*16}=\frac{24+8\sqrt{634}}{32}
$